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一共有y1-y19共有19個(gè)輸出，有D1-D10共10個(gè)數(shù)據(jù)寄存器，D1-D10這10個(gè)數(shù)據(jù)寄存器中的值可以是1-19中的任意一個(gè)。比如，如果D1=1則Y1動(dòng)作，
                                                                                                                                                                                                                                   如 果D1=2則Y2動(dòng)作，
                                                                                                                                                                                                                                    如果D1=3則Y3動(dòng)作。。等等，需要對D1-D10這10個(gè)數(shù)據(jù)

寄存器的值分別于1-19比較，共需要19*10=190次比較，這樣的話，程序太長，有可以簡化的嗎，哪位大神能指導(dǎo)一下嗎，麻煩了。跪求